(1+i)x^2-2x-2i=0

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Solution for (1+i)x^2-2x-2i=0 equation:


Simplifying
(1 + i) * x2 + -2x + -2i = 0

Reorder the terms for easier multiplication:
x2(1 + i) + -2x + -2i = 0
(1 * x2 + i * x2) + -2x + -2i = 0

Reorder the terms:
(ix2 + 1x2) + -2x + -2i = 0
(ix2 + 1x2) + -2x + -2i = 0

Reorder the terms:
-2i + ix2 + -2x + 1x2 = 0

Solving
-2i + ix2 + -2x + 1x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2x' to each side of the equation.
-2i + ix2 + -2x + 2x + 1x2 = 0 + 2x

Combine like terms: -2x + 2x = 0
-2i + ix2 + 0 + 1x2 = 0 + 2x
-2i + ix2 + 1x2 = 0 + 2x
Remove the zero:
-2i + ix2 + 1x2 = 2x

Add '-1x2' to each side of the equation.
-2i + ix2 + 1x2 + -1x2 = 2x + -1x2

Combine like terms: 1x2 + -1x2 = 0
-2i + ix2 + 0 = 2x + -1x2
-2i + ix2 = 2x + -1x2

Reorder the terms:
-2i + ix2 + -2x + x2 = 2x + -2x + -1x2 + x2

Combine like terms: 2x + -2x = 0
-2i + ix2 + -2x + x2 = 0 + -1x2 + x2
-2i + ix2 + -2x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
-2i + ix2 + -2x + x2 = 0

The solution to this equation could not be determined.

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